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i tried to solve it,but something wasnt right.ok anyway ill show you the way i tried to solve it
4(1)3(2)3(3)5(4)4(6)3(7)5(8)5(9)4(10)3(11)6(12)6(1 3)
what's left outside is:433543554366
(4)335(4)355(4)366:so the numbers that follow here are logical to be (4)366
if we add this to the sequence above and continue it will be:
4(1)3(2)3(3)5(4)4(6)3(7)5(8)5(9)4(10)3(11)6(12)6(1 3)4(14)3(15)6(16)6(17)
the problem here is that inside the brackets a five is missing,so instead of 15 16 and 17 there may be 16 17 and 18
Last edited by catocala_lacrymosa : 08-08-2008 at 11:01 AM
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